Value of the force is decreased by four.
F=k•q1•q2/r²
If r2=2•r1, F2=F1/4
What happens to the force between the charges if the distance between the charges is increased to two times its original value?
Value of the force is increased by two.
Value of the force is decreased by two.
Value of the force is decreased by four.
Value of the force is increased by four.
I would guess the obvious, which would be "value of the force is decreased by two."
2 answers
Value of the force is decreased by four man!
1 answer