What fraction must be subtracted from the sum of 2 1/6 and 2 7/12 to give 3 1/4?

Answer 1

To solve this problem, we need to find the fraction that must be subtracted from the sum of 2 1/6 and 2 7/12 to give 3 1/4.

First, we convert all the mixed numbers into improper fractions:
2 1/6 = 12/6 + 1/6 = 13/6
2 7/12 = 24/12 + 7/12 = 31/12
3 1/4 = 12/4 + 1/4 = 13/4

Next, we find the sum of 13/6 and 31/12:
13/6 + 31/12 = (2*13 + 1*31)/(2*6) = 113/12.

Finally, we find the fraction that must be subtracted from 113/12 to give 13/4:
113/12 - x/12 = 13/4
Multiplying both sides of the equation by 12 to get rid of the denominator, we have:
113 - x = 39
Subtracting 113 from both sides, we have:
-x = -74
Dividing both sides by -1, we have:
x = 74.

Therefore, the fraction that must be subtracted from the sum of 2 1/6 and 2 7/12 to give 3 1/4 is 74/12 or 37/6.