what force must be exerted on an electron to move it from a state of rest to a speed of 3.5 x 10^7 m/s in a distance of 0.75 m?
V^2=Vo^2+2ax
3.5x10^7=2a(0.75)
3.5x10^7=1.50a
divide by 1.50 on both sides to get "a" by itself
a = 2.3x10^7 m/s^2
next use Newton's 2nd law F=ma
F=(9.1x10^-31)(2.3x10^7) *9.1x10^-31 is the mass of the electron)
your answer is F = -1.3x10^3 Newtons
Done.
what force must be exerted on an electron to move it from a state of rest to a speed of 3.5 x 10^7 m/s in a distance of 0.75 m?
Look up the mass of the electron and call it m. Then compute the required acceleration a, using
V = sqrt(2 a X)
(Solve that for a)
For the force required, use
F = m a
2 answers
you need to Square 3.5x 10^7 so that its (3.5x 10^7)^2 / 1.50 = a
0 answers