If the carton is moved at uniform velocity ma=0
F-F(fr) –mgsinα = 0
F= F(fr) +mgsinα =μmgcosα+ mgsinα =
=mg (μ•cosα + sinα)
What force must be applied to push a carton weighing 350 N up a 19° incline, if the coefficient of kinetic friction is 0.45? Assume the force is applied parallel to the incline and the velocity is constant. (Enter the magnitude of the force.)
1 answer