Yea, you get to use F=MxA
where, M=mass, A=acceleration.
if you expand the equation, you notice
F=MxA
where A=velocity change / time taken for change
therefore, f = 1kg x (5ms/5secs)
What force is required to give a 1kg body a velocity of 5m/s after acting for 5sec?
I know I can use F=mxa
What do I do with the 5sec?
Thanks
2 answers
The basic form of Newton's second law is
Force = rate of change of momentum
= change of (m V) /time
if m is constant this is the familiar form
F = m dV/dt = m A
but here it is simple to use the more fundamental form
change of momentum/time
= m v/t = 1 *5/5 Newtons
as Francis said.
Force = rate of change of momentum
= change of (m V) /time
if m is constant this is the familiar form
F = m dV/dt = m A
but here it is simple to use the more fundamental form
change of momentum/time
= m v/t = 1 *5/5 Newtons
as Francis said.
0 answers