Asked by Anonymous
What f-1(x) of f(x)=(1/3)^x
Answers
Answered by
Damon
You want the inverse of:
y = (1/3)^x ?????
hmmm maybe try
x = (1/3)^y
ln x = y ln(1/3)
y = ln x /ln(1/3) = -ln x ln 3
y = - 1.1 ln x approximately
y = (1/3)^x ?????
hmmm maybe try
x = (1/3)^y
ln x = y ln(1/3)
y = ln x /ln(1/3) = -ln x ln 3
y = - 1.1 ln x approximately
Answered by
Steve
or, to avoid introducing a new base,
f^-1(x) = log<sub>1/3</sub>x = -log<sub>3</sub>x
log and exponentiation are inverses, just like
+ and -
* and /
square root and square
We just don't have any special symbols to denote the operation.
f^-1(x) = log<sub>1/3</sub>x = -log<sub>3</sub>x
log and exponentiation are inverses, just like
+ and -
* and /
square root and square
We just don't have any special symbols to denote the operation.
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