Imagine a "very large" kite so that D is many km below A.
Then angle D would approach 0°
and
angle A + angle C + "almost zero" + 80 = 180
2(∢A) + 80 < 180 , (remember angle A = angle C)
∢A < 50°
what do you need to know to solve this? you have kite ABCD. angle B is at the top of the kite and measures 80 degrees. angles A and C are on the sides and angle D is at the bottom of the kite. what is the largest siza that angle A or C could be?
3 answers
Shouldn't the sum of the interior angles of a quadrilateral be 360 degrees?
Of course drwls is right, how silly of me
so 2(∢A) + 80 < 360
∢A < 140°
so 2(∢A) + 80 < 360
∢A < 140°