You have two left parentheses and one right so it is not clear what you mean.
Do you mean log base 10?
What do you get when you solve this equation where t = time in hours
log t = (0.576 log (72/526) -0.176
Would it matter if t were in minutes?
Thank you
4 answers
If t is defined as time in hours in the equation, and you have time in minutes, you need to convert to hours first.
logt = (0.576log(72/526)) - 0.176.
logt = 0.576log(0.136882129) - 0.176,
logt = -0.86365- 0.176,
logt = -1.039653,
10^(-1.039653) = t,
0.091274 = t.
Or t = 0.091274.
logt = 0.576log(0.136882129) - 0.176,
logt = -0.86365- 0.176,
logt = -1.039653,
10^(-1.039653) = t,
0.091274 = t.
Or t = 0.091274.
The results would be the same regardless of what you call t.
If the problem states that t is in
minutes. Then your answer is in minutes. You can convert to what units
you desire.
If the problem states that t is in
minutes. Then your answer is in minutes. You can convert to what units
you desire.
0 answers