What do I have wrong in here?
A stone is thrown vertically upward at a speed of 60.0m/s.
a) How long after being thrown is it 175m above ground?
So i did -
d = V1t + 1/2at^2
175 = 60t + 1/2 (10)t^2 (rearranged and divided it all by 5)
0 = t^2 + 12t - 35
And I can't get the factors.
We were asked to consider acceleration as 10.0m/s^2
How do you know if a quadratic is a perfect square?
2 answers
Hey, if velocity up is +, and distance up is +, then gravity down is -
ok so call g = 9.8 which you are calling 10 close enough DOWN
175 = 60 t - 5 t^2
t^2 - 12 t + 35 = 0
(t-5)(t-7) = 0
t = 5 and t = 7
5 seconds on the way up, 7 seconds on the way down again.
175 = 60 t - 5 t^2
t^2 - 12 t + 35 = 0
(t-5)(t-7) = 0
t = 5 and t = 7
5 seconds on the way up, 7 seconds on the way down again.
2 answers