The standard form equation of a circle :
( x - h ) ^ 2 + ( y - k ) ^ 2 = r ^ 2
h are the x coordinates of the center of the circle
k are the y coordinates of the center of the circle
r = radius
In this case:
x coordinate of the center = 2
y coordinate of the center = 4
r = sqrt ( 9 ) = 3
Draw coordinate system , put driver in point ( x = 2 , y = 4 ) and drive circle with radius = 3
y coordinate
What do I do to graph:
(x-2)^2+(y-4)^2=9
2 answers
they are right