Look at resultants
I will call them L and R for left and right
a)
Slope of U = Uy/Ux
Slope of V = Vy/Vx = -1/slope of U if perpendicular = -Ux/Uy
so
Vy/Vx = - Ux/Uy
- Vx Ux = VyUy
Now U + V = (Ux+Vx)i + (Uy+Vy)j
and U - V = (Ux-Vx)i + (Uy-Vy)j
magnitude of U+V squared =
(Ux+Vx)^2 + (Uy+Vy)^2
= Ux^2 + 2 UxVx +Vx^2 +Uy^2+2 UyVy^2+Vy^2
magnitude of U-V squared =
(Ux-Vx)^2 + (Uy-Vy)^2
= Ux^2 [[[[[-2 UxVx ]]]] +Vx^2 etc.
SEE WHAT IS HAPPENING?
If UxVx= - UyVy
those middle terms disappear and the magnitudes squared are the same.
which means that + or - the square roots are the same which means the absolute values are the same
What conditions must be satisfied by the vectors "u" and "v" for the following to be true?
a) |u + v| = |u - v|
vector "u" is perpendicular to vector "v"
b) |u + v| > |u - v|
0° ≤ θ ≤ 90°
c) |u + v| < |u - v|
90° < θ ≤ 180°
------- Can you please explain to me why these conditions are true? Why is it perpendicular for the first one? Why is less less than 90°, but greater than 0° for question "b"? Why is it less than 180°, but greater than 90° for question "c"?
2 answers
No I don't understand what you did.