what coeffician can i add to KOH to make it balanced with

Question

H=2 + K=2
O=1 O=1

explain why

Answer 1

To balance the chemical equation for KOH, you need to add the appropriate coefficients to each element or compound involved. Given:

H = 2
K = 2
O = 1
O = 1

We can see that the hydrogen (H) is already balanced with a coefficient of 2 on the left side of the equation, as well as on the right side. Therefore, no additional coefficients are needed for hydrogen.

To balance the potassium (K), we see that we have 2 potassium (K) atoms on the left side of the equation (KOH), but only 1 on the right side. To equalize the number of K atoms, we need to add a coefficient of 2 in front of KOH on the right side of the equation. Therefore, the balanced equation becomes:

KOH + 1 → KOH + 1

Regarding oxygen (O), we have 1 oxygen atom on the left side of the equation (KOH), but 2 oxygen atoms on the right side (H2O). To balance the oxygen, we need to add a coefficient of 2 in front of KOH on the left side, making the equation:

2KOH + 1 → KOH + 2

So, the coefficients required to balance the equation KOH + H2O → KOH are 2 in front of KOH and 2 in front of H2O.