What average net force is required to accelerate a 9.5 g bullet from rest to 650 m/s over a distance of 0.85 m along the barrel of a rifle?

Answer 1

I will teach you how to do the problem with different numbers so you can do it by yourself and learn. I learned this last year.

What average force is needed to accelerate a 7.00-gram pellet from rest to 125m/s over distance of a .800m along the barrel of a rifle?

You would do a = (V^2-Vo^2)/2d.
a = (15625-0)/1.60 = 9766 m/s^2.

F = ma = 0.007 * 9766 = 68.4 N.

Hope this helps! Make sure you understand this question.

Answer 2

I know how to do it but I keep getting the wrong answer

Answer 3

V^2 = Vo^2 + 2ad = 650^2.
0 + 1.7a = 650^2,
a = 248,529 m/s^2.

F = M*a = 0.0095 * 248,529 =

=

Answer 4

thank you

Answer 5

Where did you get 0.0095?

Answer 6

.0095 came from converting g to kg