What are you supposed to get when you factor 3q^2+16q=-5? I got (q+3)(3q+1)

Answer 1

3q^2+16q= -5
3q^2+16q+5 = 0 now look for factors of 15 that add to be 16 (1 &15)

so (3q + 1)(q +1) = 0

so (3q + 1) = 0 and/or (q +1) = 0

so{-1/3, -1} are your possible solutions

Answer 2

How did you get (3q + 1)(q +1) = 0? What happened to the 15?

Answer 3

There is a typo in the previous information.

3q^2 + 16q + 5 = (3q + 1)(q + 5) = 0

3 * 5 = 15

so q could = -1/3 or -5

This should make it clearer. Thanks for asking.