To find the values of a, b, and f in the equation 5x^2 + 12x = 8, we need to first rewrite the equation in the standard form of a quadratic equation, which is ax^2 + bx + f = 0.
Given equation: 5x^2 + 12x = 8
Subtract 8 from both sides: 5x^2 + 12x - 8 = 0
Now we can see that a = 5, b = 12, and f = -8.
Therefore, the values of a, b, and f in the equation 5x^2 + 12x = 8 are:
a = 5
b = 12
f = -8
What are values of a,b,f
5x^2+12x=8 please
5 answers
I meant to write a,b,c not f. How is it -8 please
My apologies for the confusion. In the standard form of a quadratic equation, it is common to use the variable c instead of f. Let's correct the values of a, b, and c in the equation 5x^2 + 12x = 8:
Given equation: 5x^2 + 12x - 8 = 0
Now we can see that a = 5, b = 12, and c = -8.
Therefore, the values of a, b, and c in the equation 5x^2 + 12x = 8 are:
a = 5
b = 12
c = -8
Given equation: 5x^2 + 12x - 8 = 0
Now we can see that a = 5, b = 12, and c = -8.
Therefore, the values of a, b, and c in the equation 5x^2 + 12x = 8 are:
a = 5
b = 12
c = -8
How do you come to -8 for the answer?
Apologies for the oversight in the previous responses. Let's correct the calculation for the equation 5x^2 + 12x = 8:
Given equation: 5x^2 + 12x = 8
To find the values of a, b, and c in the standard form ax^2 + bx + c = 0, we need to subtract 8 from both sides to set the equation equal to zero:
5x^2 + 12x - 8 = 0
Now we can see that a = 5, b = 12, and c = -8.
Therefore, the values of a, b, and c in the equation 5x^2 + 12x = 8 are:
a = 5
b = 12
c = -8
Given equation: 5x^2 + 12x = 8
To find the values of a, b, and c in the standard form ax^2 + bx + c = 0, we need to subtract 8 from both sides to set the equation equal to zero:
5x^2 + 12x - 8 = 0
Now we can see that a = 5, b = 12, and c = -8.
Therefore, the values of a, b, and c in the equation 5x^2 + 12x = 8 are:
a = 5
b = 12
c = -8
1 answer