What are the x intercepts of the function below?

G (x) = (4x . - 1)(x+2)

1 answer

To find the x-intercepts of the function \( G(x) = (4x - 1)(x + 2) \), we need to set the function equal to zero and solve for \( x \):

\[ G(x) = 0 \]

This gives us the equation:

\[ (4x - 1)(x + 2) = 0 \]

We can solve this by setting each factor equal to zero:

  1. \( 4x - 1 = 0 \)
  2. \( x + 2 = 0 \)

Solving the first equation:

\[ 4x - 1 = 0 \]

Add 1 to both sides:

\[ 4x = 1 \]

Now, divide by 4:

\[ x = \frac{1}{4} \]

Solving the second equation:

\[ x + 2 = 0 \]

Subtract 2 from both sides:

\[ x = -2 \]

Thus, the x-intercepts of the function \( G(x) \) are:

\[ x = \frac{1}{4} \quad \text{and} \quad x = -2 \]

In summary, the x-intercepts are:

\[ \left( \frac{1}{4}, 0 \right) \quad \text{and} \quad (-2, 0) \]