pH = 3.86
pH + pOH = pKw = 14
You know pH and pKw, solve for pOH.
Then pH = -log(H^+). Solve for (H^+).
and pOH = -log(OH^-). Solve for (OH^-).
What are the values of [H3O+] and [OH−] for a solution with pH = 3.86?
1 answer