The dilution formula works for these.
2M x [60/(60+455)] = ??M
You have diluted it by a factor of 60/515. That assumes the volumes are additive (and you can't be sure they are).
What are the steps in solving this problem? There was 455 mL of water added to 60 mL of a 2M ammonia solution. What is the new molarity?
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