What are the solutions to the quadratic equation 3(x+5)(x−7)=0?
4 answers
One way to solve is to expand the equation and then use the quadratic equation to solve for x.
Solving an equation whose product is zero is by setting each factor to zero.
3 ( x + 5 ) ( x − 7) = 0
Divide both sides by 3
( x + 5 ) ( x − 7) = 0
x + 5 = 0 ⇒ x = - 5
x - 7 = 0 ⇒ x = 7
The solutions are x = - 5 and x = 7
3 ( x + 5 ) ( x − 7) = 0
Divide both sides by 3
( x + 5 ) ( x − 7) = 0
x + 5 = 0 ⇒ x = - 5
x - 7 = 0 ⇒ x = 7
The solutions are x = - 5 and x = 7
So the answers 5?
Bosnian's approach is much better.