To solve the equation x^2 - 4x - 5 = 0, we can use the quadratic formula. The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the solutions are given by:
x = (-b ± √(b^2 - 4ac)) / 2a
In this case, a = 1, b = -4, and c = -5. Substituting these values into the formula, we get:
x = (4 ± √((-4)^2 - 4*1*(-5))) / 2*1
x = (4 ± √(16 + 20)) / 2
x = (4 ± √36) / 2
x = (4 ± 6) / 2
Therefore, the solutions to the equation x^2 - 4x - 5 = 0 are:
x = (4 + 6) / 2 = 10 / 2 = 5
x = (4 - 6) / 2 = -2 / 2 = -1
So, the solutions are x = 5 and x = -1.
What are the solutions to the equation x2−4x−5=0
?
1 answer
1 answer