what are the solutions to 2x^2+7x=4? Select all that apply.

1/2
4
-1/2
-4
7
-7

1 answer

The solutions are 1/2 and -4.

To find these solutions, we first need to rearrange the equation to set it equal to zero:
2x^2 + 7x - 4 = 0

Now we can factor the equation or use the quadratic formula. Factoring the equation gives us:
(2x - 1)(x + 4) = 0

Setting each factor equal to zero, we find the solutions:
2x - 1 = 0
2x = 1
x = 1/2

and
x + 4 = 0
x = -4

Therefore, the solutions are 1/2 and -4.