What are the solutions of the system?

Question

y = x2 + 3x – 4
y = 2x + 2

Don't understand

Answer 1

Eq1: Y = x^2+3x-4
Eq2: Y = 2x+2

In Eq1, replace Y with 2x+2 and solve for X:
2x+2 = x^2+3x-4
x^2+3x-2x = 2+4
x^2+x = 6
x^2+x-6 = 0
C = -6 = -2*3.
(x-2)(x+3) = 0

x-2 = 0, X = 2.
x+3 = 0, X = -3.

Solution: X = -3, and 2.