To solve the quadratic equation \( 49x^2 = 9 \), we start by rearranging it into standard form:
\[ 49x^2 - 9 = 0. \]
Next, we can factor the left-hand side:
\[ (7x - 3)(7x + 3) = 0. \]
Setting each factor equal to zero gives us the solutions:
- \( 7x - 3 = 0 \) leads to \( 7x = 3 \) or \( x = \frac{3}{7} \).
- \( 7x + 3 = 0 \) leads to \( 7x = -3 \) or \( x = -\frac{3}{7} \).
Thus, the solutions to the equation \( 49x^2 = 9 \) are:
\[ x = \frac{3}{7} \quad \text{and} \quad x = -\frac{3}{7}. \]
Therefore, the correct answer is:
x = Start Fraction 3 Over 7 End Fraction and x = Start Fraction negative 3 Over 7 End Fraction.