To find the solutions of the quadratic equation 2x^2 – 16x + 32 = 0, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this equation:
a = coefficient of x^2 term = 2
b = coefficient of x term = -16
c = constant term = 32
Plugging these values into the quadratic formula:
x = (-(-16) ± √((-16)^2 - 4(2)(32))) / (2(2))
x = (16 ± √(256 - 256)) / 4
x = (16 ± √0) / 4
Since the discriminant (b^2 - 4ac) is equal to zero, the square root of zero is zero. Therefore, we have:
x = (16 ± 0) / 4
x = 16 / 4
x = 4
So the quadratic equation 2x^2 – 16x + 32 = 0 has only one solution, which is x = 4.
What are the solutions of the quadratic equation?
2x^2 – 16x + 32 = 0
1 answer