What are the solutions for x when y is equal to 0 in the following quadratic function?
y=x^2+10x-24
A. x = –4 or x = –6
B. x = –6 or x = 4
C. x = –2 or x = 12
D. x = –12 or x = 2
E. no real solutions
2 answers
wait is this D?
x^2+10x-24 = 0
(x+12)(x-2) = 0
Looks like D to me.
(x+12)(x-2) = 0
Looks like D to me.