What are the roots of f(x)=6x2+216 ?(1 point)

Responses

±6
plus or minus 6

±36
plus or minus 36

±36i
plus or minus 36 i

±6i

1 answer

To find the roots of the function \( f(x) = 6x^2 + 216 \), we can set it equal to zero:

\[ 6x^2 + 216 = 0 \]

Now, we can isolate \( x^2 \):

\[ 6x^2 = -216 \]

\[ x^2 = -36 \]

Next, we take the square root of both sides:

\[ x = \pm \sqrt{-36} \]

Since \(\sqrt{-36} = \sqrt{36} \cdot i = 6i\), we have:

\[ x = \pm 6i \]

Thus, the roots of the function \( f(x) = 6x^2 + 216 \) are:

±6i

So the correct response is: ±6i (plus or minus 6 i).