What are the possible values of y in the ordered pair (12, y) located in quadrant 1

y=

1 answer

In quadrant 1 of the Cartesian coordinate system, both the x-coordinate and y-coordinate must be positive. The given ordered pair is (12, y), where the x-coordinate is 12. Since 12 is positive, for the point to be in quadrant 1, the value of \( y \) must also be greater than 0.

Therefore, the possible values of \( y \) are:

\[ y > 0 \]

This means any positive value for \( y \) will keep the ordered pair (12, y) in quadrant 1.