1. Set the two equations equal to each other: 250 + 200h = 300 + 180h
2. Solve for h by moving all terms with h to one side and constants to the other side: 250 + 200h - 180h = 300
3. Simplify: 250 + 20h = 300
4. Solve for h: h = 50 / 20
5. h = 2.5 credit hours
So, a student will have to take 2.5 credit hours for the two tuition costs to be equal.
What are the possible steps involved in solving the equation shown? Select three options.
The tuition costs, C, for a local community college are modeled by C(h) = 250 + 200h, where h represents the number of credit hours taken. The local state university has tuition costs, S, modeled by the function S(h) = 300 + 180h.
How many credit hours will a student have to take for the two tuition costs to be equal? Round the answer to the nearest tenth of an hour.
1. 250 + 200h = 300 + 180h
2. 250 + 200h = 300 + 180h
− 180h − 180h
3. 250 + 20h = 300
h = ________ credit hours
1 answer