Prob(3heads) = (1/2)^3 = 1/8
so prob(not three heads) = 7/8
so odds against 3 heads is 7:1
What are the odds against getting three heads in three successive flips of a coin?
Odds against A = (1 – 3/6)/ (3/6)= 3/5 = 3::5
Could someone check my answer and correct me if I need it please
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