what are the non-permissible value for the rational expression (x^2 + x -6) / (x^2 + x -12)?

Question

a) x = 0 and x = -2
b) x = 0 and x = -4
c) x = 2 and x = -3
d) x = 3 and x = -4

Answer 1

The non-permissable values results in
a denominator of 0.Let X^2+X-12=0,
Solve for X by factoring:(X+4)*(X-3)=0
X+4=0, X=-4; X-3=0, X=3. Ans.= d

Answer 2

thanks henry

Answer 3

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