assume 1000g of solution
so 301 grams of it is formic acid, and 699 grams of water.
moles of water=699/18= ...
moles of formic acid=301/molmass=..
mole fraction=molesacid/totalmoles
molality= molesacid/.699
What are the molality and mole fraction of solute in a 30.1 percent by mass aqueous solution of formic acid (HCOOH)
can you please explain it better? I still don't quite understand
2 answers
Daryll, "Explain it further" doesn't help much. Did you try following each of the formulas I gave. Exactly what do you not understand. Do it step by step, show your work, and explain each part you don't understand.