In a 100 g sample, you will have 30.1 g HCOOH and 69.9 g H2O.
mols HCOOH = 30.1/molar mass = ?
Then m = mols HCOOH/0.1 kg solvent = ?
XHCOOH = mols HCOOH/total mols.
You have mols HCOOH. mols H2O \ grams H2O/molar mass = ?
What are the molality and mole fraction of solute in a 30.1 percent by mass aqueous solution of formic acid (HCOOH)
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