Your Ka is right but I would have written H3O^+ on the right instead of H^+.
Your Kb shows HSO3^- donating a proton to H2O; therefore, that is an acid reaction. You want it accepting a proton.
HSO3^- + H2O ==> H2SO3 + OH^-
Kb = (H2SO3)/(H^+)(HSO3^-)
What are the ka and kb reactions of NaHSO3 ?
I tried it out and thought it would be
ka= HSO3-(aq) + H2O(l)= H+(aq) + SO3-(aq)
kb= HSO3-(aq) + H2O(l)= H3O+(aq)+ OH-(aq)
Would that be right? or is it wrong? please can you take a look at it . Thanks.
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