What are the graphs of y = cos x and y = sec x in the interval from -2pi to 2pi?
5 answers
Please do not use my name as a school subject.
You should be familiar with the cosine curve
The cosine curve runs from -1 to +1.
cos(0) = 1
cos(60°) = 1/2
cos(90) = 0
cos(120) = -1/2
etc
since secx = 1/cosx
at any given x , the secant is the reciprocal of the cosine value
e.g. cos(60) = 1/2, thus sec(60) = 2
which means that when the cosine value is zero, (as it crosses the x-axis) , we would have the reciprocal of zero , which of course is undefined
So we have vertical asymptotes whenever the cosine value is 0.
The result is a series of U shaped curves sitting on top or falling below the cosine curve as you can seen in the graph I gave you
The cosine curve runs from -1 to +1.
cos(0) = 1
cos(60°) = 1/2
cos(90) = 0
cos(120) = -1/2
etc
since secx = 1/cosx
at any given x , the secant is the reciprocal of the cosine value
e.g. cos(60) = 1/2, thus sec(60) = 2
which means that when the cosine value is zero, (as it crosses the x-axis) , we would have the reciprocal of zero , which of course is undefined
So we have vertical asymptotes whenever the cosine value is 0.
The result is a series of U shaped curves sitting on top or falling below the cosine curve as you can seen in the graph I gave you
yes. that is right. and good morning mrs. sue
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my mind has been shattered by these revelations
3 answers