y^2/9 - x^2/16 = 1
so, what are the foci of y^2/a^2 - x^2/b^2 = 1?
What are the foci of the hyperbola with equation 16y^2-9x^2=144
4 answers
why cant you just give the answer?!?!?!?!?!?
Answer is (0plus or minus 5)
16y + 0 = 16y
1 answer