What are the first four terms of the sequence represented by the expression 3n+8 ?

Answer 1

When n=1, we have 3(1)+8=11 as the first term.

When n=2, we have 3(2)+8=14 as the second term.

When n=3, we have 3(3)+8=17 as the third term.

When n=4, we have 3(4)+8=20 as the fourth term.

Therefore, the first four terms of the sequence represented by the expression 3n+8 are:

11, 14, 17, 20.