What are the first 4 terms in the sequence represented by the expression 2n+3?
A. 2,5,8,11
B. 4,5,6,7
C. 5,7,9,11
D. 5,10,15,20***
7 answers
try plugging in one thru four for n
sorry im clueless when it comes to math
can someone help me pls??
yes ... I do believe "clueless"
substitute the values 1, 2, 3, and 4 for "n" in the given expression
substitute the values 1, 2, 3, and 4 for "n" in the given expression
follow R_scott's suggestion
when n = 1 , 2n+3 = 2(1) + 3 = 5
when n = 2 , 2n+3 = 2(2) + 3 = 7
when n = 3, 2n+3 = 2(3) + 3 = 9
....
What do you notice about the output numbers?
How does that tie in with 2n+3 ?
The excuse " I am clueless in math" is such a lame one.
With a little bit of effort and trying to understand what you are doing
will bring you away from being "clueless"
when n = 1 , 2n+3 = 2(1) + 3 = 5
when n = 2 , 2n+3 = 2(2) + 3 = 7
when n = 3, 2n+3 = 2(3) + 3 = 9
....
What do you notice about the output numbers?
How does that tie in with 2n+3 ?
The excuse " I am clueless in math" is such a lame one.
With a little bit of effort and trying to understand what you are doing
will bring you away from being "clueless"
So would it be C?
The answer to this is A
2+3x1= 5
2+3x2= 8
2+3x3= 11
2 is the starting number leading to the sequence of 2,5,8,11 meaning A is the answer
2+3x1= 5
2+3x2= 8
2+3x3= 11
2 is the starting number leading to the sequence of 2,5,8,11 meaning A is the answer