The excluded values of the function are the values of x that make the denominator of the fraction equal to zero. In this case, the denominator is 6x + 72. Therefore, the excluded value of x would be any value that makes 6x + 72 equal to zero.
Solving 6x + 72 = 0 for x, we get:
6x + 72 = 0
6x = -72
x = -12
Therefore, the excluded value for x in the function y = 5 / (6x + 72) is x = -12.
What are the excluded values of the function? y equals 5 over the quantity 6 times x plus 72
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