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What are the coordinates of the points at which the slope of a function with the equation y=x^4-8x^2 is equal to zero?

Please help me to understand how to approach this question.

2 answers

y'=0=4x^3-16x= 4x(x+2)(x-2)

so what are the zeroes of this?

Is it (0,0), (2,0) and (-2,0)?

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