What are the coordinates of the minimum point for the square root function that relates to the quadratic function f(x)=12(x−11)2+4 ?

Answer 1

The given quadratic function is \( f(x) = 12(x - 11)^2 + 4 \).

To find the minimum point, we observe that this function is in vertex form, which is \( f(x) = a(x - h)^2 + k \), where \((h, k)\) is the vertex of the parabola.

In this case, we can identify:

• \( a = 12 \) (which is positive, indicating the parabola opens upwards)
• \( h = 11 \)
• \( k = 4 \)

Thus, the coordinates of the minimum point (the vertex) of the function \( f(x) \) are \((h, k) = (11, 4)\).

Therefore, the coordinates of the minimum point are \((11, 4)\).