What are the coefficients for the reaction _Cl2O5 + _H2O → _HClO3 once it is balanced?

Question

1, 1, 1
1, 1, 2
1, 2, 2
2, 1, 1

Answer 1

To balance the reaction \( \text{Cl}_2\text{O}_5 + \text{H}_2\text{O} \rightarrow \text{HClO}_3 \), we can follow these steps:

1. Identify the number of each atom on both sides:

   • Reactants:

     • Cl: 2 (from Cl2O5)
     • O: 5 (from Cl2O5) + 1 (from H2O) = 6
     • H: 2 (from H2O)

   • Products:

     • Cl: 1 (from HClO3)
     • O: 3 (from HClO3)
     • H: 1 (from HClO3)

2. Start balancing Cl:

   • We have 2 Cl atoms in the reactants, so we need 2 HClO3 in the products: \[ \text{Cl}_2\text{O}_5 + \text{H}_2\text{O} \rightarrow 2 \text{HClO}_3 \]

3. Update the count of products:

   • Reactants:
     • Cl: 2
     • O: 5 + 1 = 6
     • H: 2
   • Products:
     • Cl: 2 (from 2 HClO3)
     • O: 3 × 2 = 6 (from 2 HClO3)
     • H: 1 × 2 = 2 (from 2 HClO3)

4. Confirm the balance:

   • Cl: 2 = 2
   • O: 6 = 6
   • H: 2 = 2

The balanced equation now looks like: \[ \text{Cl}_2\text{O}_5 + 2 \text{H}_2\text{O} \rightarrow 2 \text{HClO}_3 \]

Thus, the coefficients are:

• For Cl2O5: 1
• For H2O: 2
• For HClO3: 2

This corresponds to the option 1, 2, 2.