What are the boiling point of a solution prepared by dissolving 2.40g of biphenyl(C^12H^10) in 75.0g of benzene? The molecular weight of biphenyl is 154..

Answer 1

moles biphen = grams/molar mass
Solve for moles.

m = moles/kg solvent.
Solve for m = molality

delta T = Kb*m
Solve for delta T, then add to 100 to find the new boiling point.

Answer 2

All of the above is ok except the last line. Solve for delta T, than add to the normal boiling point of benzene</> to find the new boiling point. The adding to 100 is for water; this is a not a water solution.