To find the zeros of the quadratic function defined by the expression \( 9x^2 - 4 \), we need to set the function equal to zero and solve for \( x \):
\[ 9x^2 - 4 = 0 \]
We can rearrange this equation:
\[ 9x^2 = 4 \]
Then, divide both sides by 9:
\[ x^2 = \frac{4}{9} \]
Next, we take the square root of both sides:
\[ x = \pm \sqrt{\frac{4}{9}} = \pm \frac{2}{3} \]
Thus, the zeros of the function are:
\[ x = \frac{2}{3} \quad \text{and} \quad x = -\frac{2}{3} \]
Now, let's match these values to the answer choices provided:
- The option corresponding to \( x = \frac{2}{3} \) is F. x equals 2-thirds
- The option corresponding to \( x = -\frac{2}{3} \) is B. x equals negative 2-thirds
Thus, the correct answers are:
B and F.
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