What amount of heat will be removed if a body of heat capacity 380jk^-1 is cooled from 50°c to 20°c

1 answer

To calculate the amount of heat removed, we need to use the formula:

Q = mcΔT

Where:
Q = amount of heat removed
m = mass of the body (assume 1 kg)
c = heat capacity of the body (380 J/k·kg)
ΔT = change in temperature (50°C - 20°C = 30°C)

Substituting the given values into the formula:

Q = (1 kg)(380 J/k·kg)(30°C)
Q = 11,400 J

Therefore, 11,400 Joules of heat will be removed.