To calculate the amount of heat removed, we need to use the formula:
Q = mcΔT
Where:
Q = amount of heat removed
m = mass of the body (assume 1 kg)
c = heat capacity of the body (380 J/k·kg)
ΔT = change in temperature (50°C - 20°C = 30°C)
Substituting the given values into the formula:
Q = (1 kg)(380 J/k·kg)(30°C)
Q = 11,400 J
Therefore, 11,400 Joules of heat will be removed.
What amount of heat will be removed if a body of heat capacity 380jk^-1 is cooled from 50°c to 20°c
1 answer