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Answer they gave: 0.000148571182
Molsr Mass: PbSO4 303.26
What about this question?
Calculate the mass (g) of PbSO4 that will dissolve in 2000 mL of 0.0694 M K2SO4 solution. The equation represents the solubility process.
PbSO4 (s) Pb2+ (aq) + SO42- (aq)
Ksp = 1.7 x 10-8
2 answers
Write the expression for Ksp.
Ksp = 1.7 x 10^-8 = (Pb^+)(SO4^-2)
(Pb^+2)(0.0694)=Ksp
Solve for (Pb^+2) = ??
(PbSO4) = (Pb^+2)
solubility PbSO4 = ?? from above.
M x L = moles = ??M x 2 L
grams = moles x molar mass.
That's 0.00014857 but you need to round that to 2 s.f. which is 0.00015 grams.
Ksp = 1.7 x 10^-8 = (Pb^+)(SO4^-2)
(Pb^+2)(0.0694)=Ksp
Solve for (Pb^+2) = ??
(PbSO4) = (Pb^+2)
solubility PbSO4 = ?? from above.
M x L = moles = ??M x 2 L
grams = moles x molar mass.
That's 0.00014857 but you need to round that to 2 s.f. which is 0.00015 grams.