Well I know to calculate heat flow you use, q=ms delta t.

Question

for this experiment we mixed naoh with hcl into water.

the total mass (volume) of the mixture was 100g

the temperature change for naoh was 11.7 degrees C and for hcl it was 11.8 degrees C

now im looking to calculate heat flow

so so far i've got

q= (100.0g h20)(4.18 j/g degrees C) ( ??????) do I put the hcl or the naoh, or the average of both temperatures combined..... or am i supposed to calculate twice, once for the hcl and once for the naoh?

thanks.

Answer 1

If you want heat flow (I don't know where your going with this problem in the end), at this point I would go with doing it twice, once for HCl and once for NaOH. Depending upon where you are going, you may want to take the average latr on. By the way, someone needs to tell you that your lower case style, typical of texting till you drop, sends the wrong message. naoh, hcl, and h2o are NOT the same as NaOH, HCl, and H₂O. I'm guessing that's what you meant.

Answer 2

cach mang cong nghiep 4.0