Assume that the velocity at t=0 is zer, sinc it is "dropped" and not thrown.
The acceleration rate is a = -g = -32 ft/s^2
a) height above ground = 300 -(a/2) t^2
= 300 - 16 t^2
b) solve 300 - 16 t^2 = 0
t = sqrt (300/16) = 4.33 s
c) Solve V = -32 t when t = 4.33 s
well i have this homework question that says:
A rock is dropped from the top of a 300-ft cliff. It's velocity at time t seconds is v(t0= -32 t feet per second.
a.) Find the height of the rock above the ground at time t.
b.) How long will the rock take to reach the ground?
c.) What will be the velocity when it hits the ground?
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