To transmit the character 'A' with even parity and one stop bit, we need to construct the packet as follows:
1. Start Bit: The start bit is always 0 and indicates the start of the transmission.
2. Data Bits: The ASCII code for 'A' is 41H, which is 0100 0001 in binary. We need to add an additional bit for even parity, resulting in 7 data bits (D6 to D0). The even parity bit will be set to ensure an even number of 1s in the data bits and parity bit combined.
3. Parity Bit: The parity bit is calculated based on the data bits. In this case, since there are two 1s in the data bits (D1 and D0), the parity bit will be set to 0 to maintain even parity.
4. Stop Bit: The stop bit is always 1 and indicates the end of the transmission.
Putting it all together, the packet for transmitting 'A' with even parity and one stop bit would be:
Start Bit | D6 | D5 | D4 | D3 | D2 | D1 | D0 | Parity Bit | Stop Bit
------------------------------------------------------------------------
0 | 0 | 1 | 0 | 0 | 0 | 0 | 1 | 0 | 1
Note: The bits are written from left to right, with the start bit being the leftmost bit and the stop bit being the rightmost bit.
we want to transmit 'A' with even parity and one stop bit. draw the packet. the ASCII code for 'A' is 41H.
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