I2 is a non-polar bond. It dissolves easily in a non-polar solvent such as varsol. It does not dissolve easily in a polar solvent such as water. In varsol I2 is light to dark pink depending upon how much I2 is dissolved. In water I2 has limited solubility and that's the light yellow.
If you add more I2 it goes into the varsol. If you add more varsol it extracts more I2 from the water part.
When you add Na2S2O3 a reaction takes place as follow:
2Na2S2O3 + I2 ==> Na2S4O6 + 2NaI
We performed the lab and we have to figure out the equilibriums equation and equilibrium shift left or right because .. etc and explain in term what causes the equilibrium to shift, give formulas of reactant/ product
the procedure was
We had 6 test tubes
• 2ml of I2/Ki solution + 2 ml Varsol (retain this mixture for colour reference)
From observation, I found Varsol (top layer) colour to be pink and aqueous ( down layer) to be yellowish.
• add 2ml of Varsol to above composition
( I got no change in colour of varsol but aqueous was light yellow ) both were same
• add 2ml of water
( varsol was same pink but aqueous was light yellow)
•add 2 drop of saturated I2/ki
( I got varsol dark pink and aqueous orange (darker yellowish).
•Add saturates Na2S2O3 (add 3 drops)
I got varsol very light pink ( almost clear) and aqueous become fully clear.
• add saturated Ki (add 5 drops )
I got varsol light pink and aqueous darker yellow
Someone please help! It’s due tomorrow
2 answers
Tysm for the answer :)
but how do we figure out will the equilibrium shift left or right in each step and why? Explain
but how do we figure out will the equilibrium shift left or right in each step and why? Explain
1 answer