We mix 119 grams of oxygen gas with 176 grams of argon in a volume of 520 mL at 116 Celsius. What will be the final pressure of the gas mixture? Answer in units of atm.

2 answers

how many moles of gas do you have?
1 mole occupies 22.4L at STP
PV/T remains constant
so find P that works
mols O2 = 119/32 = ?
mols Ar = 176/39.95 = ?
Then PV = nRT
You solve for P.
V = 0.520 L
total n from above
R = 0.08206 L*atm/mol*K
T = 116 C converted to kelvin. K = 273 + C = ?
Post your work if you get stuck.
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